> > Do the math, there are 6 more vmov instructions (all between rX and sX > > registers) in the softfp versions. Ok, if one gives a stall of 20 cycles, > > how many cycles do we lose in sinf() alone?
> So, what exactly did you want to prove? Mainly that your analysis of the code was almost entirely bogus. You chose sinf as an example of a common critical routine and made a big show of the effect, predicting that softfp would be over a hundred cycles slower (6 instructions * 20 cycle stalls). In reality it's a dozen cycles either way, with softfp being faster in some circumstances. Paul -- To UNSUBSCRIBE, email to [email protected] with a subject of "unsubscribe". Trouble? Contact [email protected] Archive: http://lists.debian.org/[email protected]
