Sorry... I automatically made a link between binary data and hexadecimal
data...
You could shift 8 bits of the unsigned long into a unsigned char one at
a time, and print that character with a %c in the printf, or use
putchar() or something.
eg:
unsigned long l = 0x38c9616e;
unsigned char c;
:
:
c = (l & 0xFF000000) >> 24;
putchar(c);
c = (l & 0x00FF0000) >> 16;
putchar(c);
c = (l & 0x0000FF00) >> 8;
putchar(c);
c = l & 0x000000FF;
putchar(c);
Is this what you were looking for? I suppose you wanted something
simple, ie using printf... I'm not sure about that.
printf
(
"%c%c%c%c",
(l & 0xFF000000) >> 24,
(l & 0x00FF0000) >> 16,
(l & 0x0000FF00) >> 8,
l & 0x000000FF
);
this might be as close as you can get.
Shao Zhang wrote:
>
> But isn't %[Xx] just prints out as Hexdecimal?
> I just tried, and it prints out something like: 38c9616e
>
> which consumes 8 bytes in a file. Given that unsigned long is 32 bits,
> I want to use exactly 4 byte to represent it in order to save some
> space.
>
> Thanks.
>
> Shao.
>
> Matthew Dalton [EMAIL PROTECTED] wrote:
> > Try using %X or %x instead of %ld
> >
> > Shao Zhang wrote:
> > >
> > > Hi,
> > > If I have an unsigned long int, instead printing out its values
> > > in string using printf("%ld\n", my_var),
> > >
> > > I would like to print it out as a 4-byte binary data. Is there
> > > any easy way to do this in C.
> > >
> > > Thanks.
> > > Shao.
> > >
> > > --
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>
> --
> ____________________________________________________________________________
> Shao Zhang - Running Debian 2.1 ___ _ _____
> Department of Communications / __| |_ __ _ ___ |_ / |_ __ _ _ _ __ _
> University of New South Wales \__ \ ' \/ _` / _ \ / /| ' \/ _` | ' \/ _` |
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