On Wed, Jan 14, 2004 at 11:59:12AM -0600, Kent West wrote:
> I need to run a test in a .bashrc startup script to see whether the
> machine the user is logging onto is a Solaris or a Linux box (the /home
> directory is shared between the two, and paths need to be modified
> according to which OS is being logged into).
>
> Something like this:
>
> if {the first word of "uname -a" is Linux}
Why not just use 'uname', which prints Linux on Linux and SunOS on
Solaris?
In general, try either:
if [ "`uname -a | sed -e 's/ .*//'`" = Linux ]
(fairly straightforward) or:
UNAME_A="`uname -a`"
if [ "${UNAME_A%% *}" = Linux ]
(match trailing portion of variable against shell pattern ' *').
> My problem is that I don't know how to match for the first word of
> "uname -a". I've tried things like:
>
> if [ `uname -a`:0:5} = "Linux" ]
That doesn't work because I don't believe there's a syntax anything like
that in shell.
> if {awk '{ print $1 }' < `uname -a` = "Linux" ]
That doesn't work because < redirects from a file, not from the output
of a command. This would work:
if [ "`uname -a` | awk '{ print $1 }'" = Linux ]
Some would think that's clearer than my sed example above, too. :)
Note that I haven't quoted "Linux" in any of my examples, since it
doesn't contain any metacharacters, but there's no harm in doing so.
Cheers,
--
Colin Watson [EMAIL PROTECTED]
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