Hello, On Fri, May 23, 2003 at 02:45:30PM +1000, Anthony Towns wrote: > Ugh, that's an overcomplicated example. Here's a simpler one: Did you read it carefully?
> Three options, A, B and D (the default option). Quorum is 10. Votes are: > > 9 ABD > 4 BDA > > A defeauts B, 9:4; B defeats D, 13:0, A defeats D, 9:4. A is dropped because > of quorum, B wins. One more person votes: > > 9 ABD > 4 BDA > 1 BAD > > A defeats B, 9:5; B defeats D, 14:0, A defeats D, 10:4. A isn't dropped, > and wins. Voting "for" B, thus causes A to win. The effect in my example is different, and in my oppinion much more of a problem. In short: Your example: An option looses, because it fails quorum My example: The winner among the interesting options changes because an uninteresting option fails quorum. > And, as I've already posted elsewhere, you'll note there's no problem > at all here if number of votes received is twice the quorum, which, > historically, it almost always is. This it true. But then there there is some tradition of getting things right :-) Jochen -- Omm (0)-(0) http://www.mathematik.uni-kl.de/~wwwstoch/voss/index.html
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