I didn't do that, but I am sure can extrapolate that from Test 1. Test 1 is doing: foreach k/v in scanner's iterator create a new mutation with that row call putDelete
Test 3 is doing foreach k/v in scanner's iterator assign the row of first entry to 'first' var assign the row to a 'last' var After the loop is done, pass 'first' and 'last' vars to deleteRows. So, if I'd extrapolate the time without reading all rows, then we can subtract result from Test 1 from result from Test 3, i.e. for Table 1 is 196,597 - 5,702 = 190,895 (this is still way too long) -- View this message in context: http://apache-accumulo.1065345.n5.nabble.com/delete-rows-test-result-tp15569p15571.html Sent from the Developers mailing list archive at Nabble.com.