I didn't do that, but I am sure can extrapolate that from Test 1.

Test 1 is doing:
foreach k/v in scanner's iterator
    create a new mutation with that row
    call putDelete

Test 3 is doing
foreach k/v in scanner's iterator
    assign the row of first entry to 'first' var
    assign the row to a 'last' var
After the loop is done, pass 'first' and 'last' vars to deleteRows.

So, if I'd extrapolate the time without reading all rows, then we can
subtract result from Test 1 from result from Test 3, i.e. for Table 1 is
196,597 - 5,702 = 190,895 (this is still way too long)




--
View this message in context: 
http://apache-accumulo.1065345.n5.nabble.com/delete-rows-test-result-tp15569p15571.html
Sent from the Developers mailing list archive at Nabble.com.

Reply via email to