Hi,
I want to understand how RouteContext or Registry register and then look up
a new Processor object when receive some DSL which contains new Processor
object, like the following one:
{code}
MyValidator validator = new MyValidator();
from("direct:start")
.doTry()
.process(validator).to("mock:valid")
.doCatch(ValidationException.class)
.to("mock:invalid")
{code}
1. Does the route/processor definition maintain the processor name
"validator" somewhere?
2. If the processor is registered, how can I get the object and translate it
into a processor reference when rendering it. I want to render the above DSL
into:
{code}
from("direct:start")
.doTry()
.processRef("someName or some
registeredKey").to("mock:valid")
.doCatch(ValidationException.class)
.to("mock:invalid")
{code}
Thanks
JIRA j...@apache.org wrote:
>
> groovy renderer
> ---------------
>
> Key: CAMEL-1392
> URL: https://issues.apache.org/activemq/browse/CAMEL-1392
> Project: Apache Camel
> Issue Type: Sub-task
> Reporter: James Strachan
>
>
>
>
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