On 29/07/2013, at 6:16 PM, kelemen <attila.keleme...@gmail.com> wrote:
> Adam: I was worried about how to provide a proper classpath. I forgot the
> dynamic nature of Groovy. However, still the serialized (?) action to be
> executed needs to be on the classpath.
We have some tricks we can use to infer for the action's classpath. So, this
should be transparent to the action and the client.
>
> Alex: I can't see how it is possible (if it is) in your proposal to retrieve
> models for mutliple evaluated projects in a single call (I'm not sure if
> traversing the project tree is possible when configuration on demand is
> used). Also how will the Gradle process be able to deserialize
> ConsumerAction? That is, how does it know the required classpath for the
> implementation of ConsumerAction? So, I would adjust your code somehow like
> this:
>
> public interface ConsumerAction<T> extends Serializable {
> Map<String, T> execute(Project... project);
> }
>
> public interface ConsumerActionExecutor {
> <T> Map<String, T> execute(ConsumerAction<T> action, ActionClassPath
> classPath);
> }
>
> Assuming a method: ConsumerActionExecutor
> ProjectConnection.actionExecutor(). The Maps above would map the fully
> qualified name of the project (e.g.: ":sub:leaf") to the model.
>
> I'm not sure what ActionClassPath should be. Perhaps a set of jar files?
> Using a set of jar files would disallow using classes loaded otherwise but
> do we need such classes?
>
> Also, I have changed ConsumerActionExecutor to work similar to an Executor
> of Java. I don't care much about it though.
>
>
>
> --
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--
Adam Murdoch
Gradle Co-founder
http://www.gradle.org
VP of Engineering, Gradleware Inc. - Gradle Training, Support, Consulting
http://www.gradleware.com
