Ellery Newcomer wrote: > according to the spec, > > a op= b; > > is semantically equivalent to > > a = a op b; > > but this doesn't seem to be strictly true.
It's untrue in several ways. For example: SomeReferenceType a, b; a = a + b; // Creates new object. b += c; // Modifies an object in place. and of course: a = a = c; // Dual assignment. a == b; // Equality comparison. -- Rainer Deyke - rain...@eldwood.com
