On Tuesday, 16 March 2021 at 13:52:29 UTC, Per Nordlöw wrote:
On Tuesday, 16 March 2021 at 13:31:34 UTC, Imperatorn wrote:
foreach(0..n) could work. Why though.

When performing a side-effect n times.

Then why not just do:

auto times(alias F, T)(T number)
{
    return number.iota.each!(_ => F());
}

void f()
{
    writeln("hi");
}

n.times!(f);

?

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