? No. If it was unsatisfied constraint, the error would've shown that.
And if you try to instantiate it, you'll see it is an unsatisfied constraint anyway. There's two layers of failure here.
Using Unqual there is pretty iffy, i wouldn't bother with it at all, but if you do anything, instead qualify it const.
But either way, then the constraint still fails since int isn't unsigned.
I'd really recommend simplifying this a lot.
