On Saturday, 11 December 2021 at 23:44:59 UTC, Adam Ruppe wrote:
On Saturday, 11 December 2021 at 23:17:17 UTC, Stanislav Blinov
wrote:
? No. If it was unsatisfied constraint, the error would've
shown that.
And if you try to instantiate it, you'll see it is an
unsatisfied constraint anyway. There's two layers of failure
here.
Using Unqual there is pretty iffy, i wouldn't bother with it at
all, but if you do anything, instead qualify it const.
But either way, then the constraint still fails since int isn't
unsigned.
I'd really recommend simplifying this a lot.
??? There is no unsatisfied constraint, it doesn't get there :)
unq.d(6): Error: template `unq.foo2` cannot deduce function
from argument types `!()(int)`
unq.d(2): Candidate is: `foo2(T)(Unqual!T x)`
...because passed argument - `int` - becomes `Unqual!T`, making
`T` unknown - template arg list is empty. Deduction fails :) If
`int` is an `Unqual!T`, what is `T`? The constraint is testing
`T`.
Now, if you explicitly instantiate - sure, you'd get unsatisfied
constraint. But the OP seems to want IFTI, which simply can't
work here.
@apz28, I can't figure out the intent here. To convert result of
abs to an unsigned?
