On Monday, 2 May 2022 at 19:17:19 UTC, Stanislav Blinov wrote:
On Monday, 2 May 2022 at 16:29:05 UTC, Loara wrote:
Template deduction for aliased function parameter is a very
tricky argument and it's not so simple to handle in certain
cases. Consider for example this code:
```d
template MyAlias(T){
alias MyAlias = int;
}
T simp(T)(MyAlias!T val){
return T.init;
}
int main(){
simp(3);//Impossible to deduce T
Why? That's the issue. It is very possible to deduce T here.
Compiler just isn't trying. The function takes an int. Doesn't
take a rocket scientist to figure that one out.
No, an alias is not a type and it'll be immediately
substitutedwith the aliased symbol. You should use
[typedefs](https://dlang.org/phobos/std_typecons.html#Typedef) in
order to create a different type.
