On 25.02.2012 20:25, Ashish Myles wrote:
I want to define a general-purpose centroid computer for point containers
and ran into a couple of challenges. Firstly, here is the basic code
Point3 computeCentroid(PointContainer)(const ref PointContainer C)
if (...) // want a signature constraint for usability of foreach
{
Point3 c = Point3(0.0, 0.0, 0.0);
size_t total = 0;
foreach(Point3 p; C) { // enforce that the container supports this
c += p; ++total;
}
if (total> 0)
c /= cast(double)(total);
return c;
}
I want to have the most generally-applicable version of this functionality
(for const/immutable/etc containers supporting foreach in various ways),
ideally without needing to write multiple versions of this function.
1. Since support for foreach can be added in many ways (with
ref/non-ref/const variants), I wanted to check if there was any
signature constraint that could check if the container supports foreach
as above. I looked into the "compiles" traits, but that doesn't work for
statements.
For an opAssign version, I had tried
if (is(typeof(C.opApply(delegate(const ref Point3) { return 1;}))))
but this is unelegant because the container's opApply could have instead
supplied delegate(Point3) or delegate(ref Point3) (although the latter
would require me to not use a "const" on the parameter declaration).
2. Secondly, TDPL on page 381 says that foreach iterates over C[], if
C defines the opSlice() function without any arguments.
However the code above doesn't seem to work and requires me to
explicitly invoke the slice operator myself like
foreach(p; C[]) { ... }
when my data structure clearly defines the following functions.
Point3[] opSlice() { return _cpts[]; }
const (Point3)[] opSlice() const { return _cpts[]; }
Is this a misunderstanding on my part or an unimplemented feature?
It's supposed to work.
I think it's just not implemented yet.
3. A more general question: Is there any by any chance a way to avoid the
redundancy above of defining two opSlice() functions (or two opAssign()
functions if I went that route -- one for const and another for ref)?
I suspect that the answer is no, but I just wanted to verify.
--
Dmitry Olshansky