Re: convert ubyte[k..k + 1] to int

[Robert DaSilva]

On Wednesday, 16 May 2012 at 18:47:55 UTC, Jonathan M Davis wrote:
As long as you're going from big endian to little endian,
std.bitmanip.bigEndianToNative will do the conversion fairly 
easily, but if
they're in little endian, then the nasty casting is the way to 
go.

- Jonathan M Davis

Except they don't take slices. You need a helper function.

ubyte[2] _2(ubyte[] a){ubyte[2] b; assert(a.length==2); b[]=a; 
return b;}