On Tuesday, 12 June 2012 at 17:40:40 UTC, Jonathan M Davis wrote:
On Tuesday, June 12, 2012 19:28:38 TJB wrote:
I am working with some financial data that comes in binary
files.
It has two fields in particular that I am trying to convert to
human readable formats. The first is a date string like
"20060621", which I am able to work with just fine. But then it
has a field called ttim, which is the number of seconds from
midnight at which a trade occurred. For example, a trade
occurring at 28824 seconds in the day would have taken place at
"8:00:24" (only resolution to the second).
My question is: how do I convert the number of seconds (like
28824) to a formatted time string (like 08:00:24)? I looked in
std.datetime, but it isn't obvious which functions I should
use.
You help and suggestions are much appreciated!
import std.datetime;
import std.stdio;
void main()
{
auto ttm = 28824;
auto duration = dur!"seconds"(ttm);
auto time = TimeOfDay.init + duration;
writeln(time.toISOExtString());
}
- Jonathan M Davis
Awesome! In the D community you get questions answered by the
library writers! Thanks so much! This was perfect.
TJB
