On Thursday, June 14, 2012 18:32:18 Roman D. Boiko wrote: > On Thursday, 14 June 2012 at 16:24:43 UTC, Jonathan M Davis wrote: > > On Thursday, June 14, 2012 17:32:03 Roman D. Boiko wrote: > >> I don't know how to put a variable of type float to the heap > > > > auto f = new float; > > *f = 2.1; > > > > - Jonathan M Davis > > Except for immutable I would need to cast when passing into a > function. That's dangerous, given that *f might be changed later. > But looks like Timon's suggestion from my other question should > work. > > immutable a = [2.1].ptr;
Yeah. That'll probably work. I wish that you could do auto f = new float(2.1); and therefore auto f = new immutable(float)(2.1); but you can't. You _can_ do auto f = new float; *f = 2.1; immutable g = cast(immutable float*)f; and that's safe, because there are no other references to the data, but it's certainly not all that desirable. The slightly more idomatic way to do it is auto f = new float; *f = 2.1; immutable g = std.exception.assumeUnique(f); But it's doing the same thing and you have to worry about the same safety issues. However, if Timon's suggestion works, that's great. - Jonathan M Davis
