Re: a FOR loop and floating variables

[Simen Kjaeraas]

On 2013-05-02, 20:14, Carlos wrote:

I have this code :

import std.stdio;
import std.c.stdlib;
void main()
{
int fahr;
write("F\tC\n");
for (fahr = 0; fahr <= 300; fahr = fahr + 20)
write(fahr, "\t", (5.0/9.0)*(fahr-32), "\n");
write("Done!\n");
exit (0);
}

Which works. but if I change the "5.0" for "5" I get cero on the celsius side.

import std.stdio;
import std.c.stdlib;
void main()
{
int fahr;
write("F\tC\n");
for (fahr = 0; fahr <= 300; fahr = fahr + 20)
write(fahr, "\t", (5/9)*(fahr-32), "\n");
write("Done!\n");
exit (0);
}

So why is this ?

Both 5 and 9 in the second example are integers (int). When you divide
one int by another, the result is an int, and hence (5/9) is 0.

--
Simen