Dne 2.5.2013 20:14, Carlos napsal(a):
I have this code :
import std.stdio;
import std.c.stdlib;
void main()
{
int fahr;
write("F\tC\n");
for (fahr = 0; fahr <= 300; fahr = fahr + 20)
write(fahr, "\t", (5.0/9.0)*(fahr-32), "\n");
write("Done!\n");
exit (0);
}
Which works. but if I change the "5.0" for "5" I get cero on the
celsius side.
import std.stdio;
import std.c.stdlib;
void main()
{
int fahr;
write("F\tC\n");
for (fahr = 0; fahr <= 300; fahr = fahr + 20)
write(fahr, "\t", (5/9)*(fahr-32), "\n");
write("Done!\n");
exit (0);
}
So why is this ?
Hi Carlos,
the second code performs integral division which very much behave like
floating-point division, but the fractional part is chopped off.
5/9 ~ 0.556 => 0
10/9 ~ 1.111 => 1
If you want precise (i.e. floating point) results, you have to have at
least one float or double in your equation.
This would work:
write(fahr, "\t", (5.0/9)*(fahr-32), "\n");
Regards,
Martin
