Joseph Rushton Wakeling:
If I use zip() to collate together one or more ranges, the
individual elements
get returned as a Tuple of the corresponding types.
Is there any way to get zip to label those elements, i.e. to
return e.g.
See:
http://d.puremagic.com/issues/show_bug.cgi?id=8715
I think currently you have to use map!() to replace the tuple.
Maybe am unsafe map-cast suffices:
import std.stdio, std.range, std.algorithm, std.typecons;
void main() {
auto r1 = zip(["red", "blue"], [10, 20]);
r1.writeln;
alias T2 = Tuple!(string,"col", int,"val");
r1.map!(r => T2(r[])).writeln;
r1.map!(r => cast(T2)r).writeln;
}
Bye,
bearophile
