Re: Call a function with a function pointer

[Dicebot]

On Thursday, 10 October 2013 at 15:15:45 UTC, bearophile wrote:
Namespace:
You mean like this?
----
void foo(T)(extern(C) void function(T*) func) {
                
}
----

That prints: Error: basic type expected, not extern     

In theory that's correct, in practice the compiler refuses 
that, it's in Bugzilla, so try to define the type outside the 
signature (untested):

alias TF = extern(C) void function(T*);

void foo(T)(TF func) {}

Bye,
bearophile

That is limitation of current extern - it can only be attached to 
symbol declarations, not types. AFAIK you need to do `extern(C) 
alias TF = ...` but anyway this method is very likely to break 
IFTI completely.