Yes, thanks, that syntax does work for the initialization.
The C syntax that failed for me was using the curly brace form
shown in the following link.
http://www.c4learn.com/c-programming/c-initializing-array-of-structure/
Also, I think I was trying forms of defining the struct and
initializing the array in the same line... something like this C:
static struct Suit{ int i; long lv;} suits[3] = {{1, 2L},{2,
4L},{3,9L}};
It looks to me like D requires a named struct definition in a
separate line from the array definition. If that is so, then
the C initialization of an array with an unnamed struct type,
like this, would require a struct type name.
static struct { int i; long lv;} suits[3] = {{1, 2L},{2,
4L},{3,9L}};
So, from your static intialization example, this works.
Also, the conversion of struct to tuple makes the writefln
tupleof conversion on the struct a little cleaner, since you only
have to specify the single tuple parameter.
module main;
import std.stdio;
void main()
{
struct Suit {string nm; int val; int val2; string shortNm;};
static Suit[5] suits = [
{"spades",1,6,"spd"},
{"hearts",4,10,"hrt"},
{"hearts2",4,10,"hrt2"},
{"diamonds",10,16,"dmd"},
{"clubs",11,17,"clb"}
];
foreach (member; suits)
{
auto tup = member.tupleof;
writefln("%s %d %d %s", tup);
}
}
prints
spades 1 6 spd
hearts 4 10 hrt
hearts2 4 10 hrt2
diamonds 10 16 dmd
clubs 11 17 clb
I also tried using writefln(tup) and writeln(tup) in the example
above. The output from writeln(tup) looks like it is headed in
the right direction. Maybe a writecsv(tup) would be useful.
spades16spd
hearts410hrt
hearts2410hrt2
diamonds1016dmd
clubs1117clb
