I'm wondering if a delegate which theoretically doesn't need to
make a heap closure, might allocate anyway.
Somehow I don't want to assume the compiler will do the
non-allocating way.
This is the code I wrote:
---
bool feed(float x, Complex!float[] fftData)
{
void processSegment(float[] segment)
{
fftData.length = _fftSize; // we do need the delegate
context here
/* do stuff with segment and fftData */
}
// _analyzer.feed takes a void delegate(float[]) as
parameter
// will this line allocate?
return _analyzer.feed(x, &processSegment);
}
---
Does the last line allocate?
