On 23/03/2014 23:01, ponce wrote:
I'm wondering if a delegate which theoretically doesn't need to make a heap closure, might allocate anyway. Somehow I don't want to assume the compiler will do the non-allocating way.This is the code I wrote: --- bool feed(float x, Complex!float[] fftData) { void processSegment(float[] segment) { fftData.length = _fftSize; // we do need the delegate context here /* do stuff with segment and fftData */ } // _analyzer.feed takes a void delegate(float[]) as parameter // will this line allocate? return _analyzer.feed(x, &processSegment); } --- Does the last line allocate?
In theory, if you use 'scope void delegate(float[])', it won't allocate. But with scope or not, it's probably best to inspect the assembly output if you need to know for sure. Perhaps using http://d.godbolt.org/ can help you do that.
