On Thursday, 22 January 2015 at 17:45:59 UTC, tcak wrote:
So, at the end of the day (I left working on my Matcher class
in the morning waiting an answer for this question), there is
nothing to convert ['a'..'d', '0'..'3'] to ['a', 'b', 'c', 'd',
'0', '1', '2', '3'] at compile time automatically.
There is rarely never a way to do something in D, if you want to
hack around a bit.
import std.stdio;
@property charRange(string spec)()
{
import std.algorithm;
import std.ascii;
import std.conv;
import std.range;
import std.string;
return spec.split(',').map!((s)
{
s = s.strip;
auto start = s[1..$].front;
auto end = s[0..$-1].back;
return iota(start, end + 1).map!(c => cast(char)c).array;
}).array.join;
}
void main(string[] argv)
{
auto t = charRange!q{ 'a'..'z', 'A'..'Z', '0'..'9' };
//abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789
writeln(t);
}
This is very rough code, as it only works for ASCII codepoints,
and it can't do backward intervals, but you get the idea.
