Re: Template type deduction and specialization

[Mike Parker via Digitalmars-d-learn]

On 5/20/2015 4:36 PM, Namespace wrote:

What about:
----
import std.stdio;
void printVal(T)(T t) {
     static if (is(T : U*, U))
         printVal(*t);
     else
         writeln(t);
}

Thanks, but I'm not looking for alternatives. I'm trying to figure out 
why it doesn't work as expected.