If I write
ubyte b = 1u; auto c = b + 1u; I expect the 1u to be of type ubyte - and also c.
Dominikus Dittes Scherkl via Digitalmars-d-learn Thu, 05 Nov 2015 02:11:02 -0800
If I write
ubyte b = 1u; auto c = b + 1u; I expect the 1u to be of type ubyte - and also c.