On Thursday, 21 July 2016 at 09:41:27 UTC, Saurabh Das wrote:
I have an interface A which declares a certain function. A second interface B inherits from A and wishes to provide a default implementation for that function.
You can't, interfaces cannot have implementations of virtual functions. Your code is trying to define two separate functions with the same name (the compiler should probably prohibit that, since it doesn't do want you want it to do).
Your best bet is to make B an abstract class instead of an interface. Then it can override interface functions. Of course, it will also tie you down as you can only inherit from one class, but it will actually work.
