On Sunday, 12 March 2017 at 20:22:33 UTC, ketmar wrote:
Meta wrote:
The reason this doesn't work is when you use ConstOf!U, it's
not looking for a `const U`, it's looking for the type
`ConstOf!U`. I'm not sure if this is a bug or not...
no, not a bug. this is the way type deconstruction works: it
checks if your type was constructed with a given template.
Yeah, it seems to be checking the pattern rather than the type.
However, ConstOf!T is just an alias for const(T), but the alias
does not seem to be "unwrapped", even though they are supposed to
be transparent.
