On 10/13/17 3:47 AM, Daniel Kozak wrote:
but it works ok with immutable, so until you really need to change bar
you can use
immutable bar = 9;
foo!byte(bar + 1);
Right, the reason why your original didn't work is the compiler
"forgets" that bar is 9 by the time it gets to the foo call. However, it
doesn't forget the value of an immutable.
On Fri, Oct 13, 2017 at 9:46 AM, Daniel Kozak <kozz...@gmail.com
<mailto:kozz...@gmail.com>> wrote:
Not sure :), I have forgoten byte+byte=int.
One place where the compiler doesn't care is +=:
bar += 400; // OK
int y = 400;
bar += y; // OK
-Steve