On Friday, 16 November 2012 at 01:02:59 UTC, Jonathan M Davis
wrote:
On Thursday, November 15, 2012 17:18:43 foobar wrote:
I thought that Haskell doesn't have function overloading (which
simplifies this greatly)... Anyway, I mostly meant "standard"
imperative/OO languages. Sorry for the confusion.
It has pattern matching (which typically results in several of
the same
function with slightly different arguments, but the overall
types are still the
same). I'm unaware of it having full-on function overloading.
But I don't
think that I've ever tried it.
- Jonathan M Davis
This article describes return type overloading in Haskell by way
of a clear example. It concludes demonstrating a real-world
implementation of the concept.
http://matthewmanela.com/blog/return-type-overloading-in-haskell/
I'm not well versed in Haskell (first look ever), so I'm not
sure, but it does seem to look like true return type overloading.
I also read an article that described Perl's overloading on
return type, but this is less like the overloading we've been
talking about, and more like a function being able to inspect the
call context to decide what type should be returned.
--rt
