On Friday, November 16, 2012 08:26:10 Jacob Carlborg wrote: > On 2012-11-15 22:08, Joseph Rushton Wakeling wrote: > > Complete misunderstanding there -- I'd interpreted Simen's remark as > > saying that e.g. auto x = 1; would automatically assign the correct type > > where builtins were concerned, and I was pointing out that this wouldn't > > cover all builtins. Though I guess auto x = 1UL; would work. > > Should this give you an unsigned long regardless of architecture? > "size_t" is unsigned int on 32bit platforms and unsigned long on 64bit > platforms.
Yeah. If you want a literal to be size_t, then you either need to assign it to a variable of type size_t or cast it. L means long and UL means unsigned long, whereas size_t varies from architecture to architecture. - Jonathan M Davis
