Re: C++ constructors, destructors and operator access

[Igor Stepanov]

Is this mean, that D functions will _not_ create C++ objects with 
new?
For example:
You have moved parser to D, but you haven't moved expressions to 
D yet.
And you want to create new Expression object in parser (in D 
code), but Expression class defined in C++. What will you do in 
this case?