On Friday, 9 August 2013 at 03:41:56 UTC, barryharris wrote:
So instead of:T t = New!T(args) you would like: T t = T.New(args) Is that it?
Never mind, I read your original post again...
Note, in this case, the type parameter is substituted.
On Friday, 9 August 2013 at 03:41:56 UTC, barryharris wrote:
So instead of:T t = New!T(args) you would like: T t = T.New(args) Is that it?
Never mind, I read your original post again...
Note, in this case, the type parameter is substituted.