On Thursday, October 17, 2013 20:31:26 Vitali wrote: > I repeat my question: "Why does a reallocation accure AFTER a > resize of the length of a slice, although there is still > capacity?"
Because it _doesn't_ have the capacity. If you do writeln(dSlice.capacity); before incrementing dSlice's length, it'll print out 0. dSlice can't grow in place, because if it did, its new elements would overlap with those of dArr; dArr -> [10, 11, 12] dSlice -> [10, 11] ++dSlice.length; dArr -> [10, 11, 12] dSlice -> [10, 11, 0] You can't make a slice cover more of another array without reslicing that array. e.g. dSlice = dArr[0 .. $] dArr -> [10, 11, 12] dSlice -> [10, 11, 12] Appending to a slice or increasing its length (which is just appending to it with the init value of its element type) is adding a new element which is not part of any other array. If there is capacity available, then that will be done in place, and the slice will still be a slice of the array that it was sliced from. But if there isn't any capacity available (and there isn't in your example, because the original array has that space), then the runtime is forced to reallocate the slice in order to make space, and then it's no longer a slice of the original array. - Jonathan M Davis
