On Sunday, 16 February 2014 at 03:16:16 UTC, Steven Schveighoffer
wrote:
On Sat, 15 Feb 2014 22:04:25 -0500, Meta <jared...@gmail.com>
wrote:
Obviously this is extremely contrived, but inout is
effectively logical const here. Is there no way to know what
the "original" mutability of t is at compile-time?
No, because only one version of the function is generated. That
is part of the benefit of inout over a template.
If you DO want to know whether it's mutable, use a template.
-Steve
If you pass a mutable value to a function taking an inout
parameter, what's the difference between that function and an
identical function that takes a regular mutable parameter instead
of an inout parameter?
