On Tue, 15 Apr 2014 11:59:31 -0400, Steven Schveighoffer
<schvei...@yahoo.com> wrote:
On the left hand side, the [] operator is special *for arrays* in that
it denotes you want to do an element-wise copy. On the right hand side,
this is not the case, [] is simply an operator. It's a no-op if the rhs
is an array, since [] just gets the array again.
Sorry, I had this wrong. The [] on the left hand side is actually part of
the []= operator. But on the right hand side, it simply is a [] operator,
not tied to the =. I erroneously thought the arr[] = ... syntax was
special for arrays, but I forgot that it's simply another operator.
My opinion is still the same.
-Steve
