On 2009-08-07 12:33:09 -0400, Miles <____...@_______.____> said:
Lars T. Kyllingstad wrote:
Neither of the natural candidates, a^b and a**b, are an option, as they
are, respectively, already taken and ambiguous.
I think that a ** b can be used, is not ambiguous except for the
tokenizer of the language. It is the same difference you have with:
a ++ b -> identifier 'a', unary operator '++', identifier 'b' (not
parseable)
a + + b -> identifier 'a', binary operator '+', unary operator '+',
identifier 'b' (parseable)
But to be coherent with a++ which does a+1, shouldn't a** mean a to the
power 1 ?
--
Michel Fortin
michel.for...@michelf.com
http://michelf.com/
