On Mon, Dec 08, 2014 at 02:52:52AM -0800, Walter Bright via Digitalmars-d wrote: > On 12/8/2014 2:44 AM, "Marc Schütz" <schue...@gmx.net>" wrote: > >On Monday, 8 December 2014 at 10:37:29 UTC, Walter Bright wrote: > >>Another problem with that is: > >> > >> void func(scope T delegate() dg); > > > >Playing the devil's advocate: > > > > void func(scope(T delegate()) dg); > > void func(scope(T) delegate() dg); > > Note that: > > void func(ref T delegate() dg); > > has the same problem. The only way to make dg return a 'ref T' is to > use an alias: > > alias ref T delegate() dg_t; > void func(dg_t dg); > > or put 'ref' as a postfix: > > void func(T delegate() ref dg); > > But if the latter solution is used for 'scope', then it interferes > with 'scope this'.
And once we start writing scope(T), we're back to scope being a type qualifier (aka type constructor) rather than merely a storage class. T -- What are you when you run out of Monet? Baroque.
