On Tuesday, 19 May 2015 at 20:46:09 UTC, Matthias Bentrup wrote:
I think you can make the over/underflow at zero work in your favor:bool isPowerOf2(uint x) { return (x & -x) > (x - 1); }
Very nice
On Tuesday, 19 May 2015 at 20:46:09 UTC, Matthias Bentrup wrote:
I think you can make the over/underflow at zero work in your favor:bool isPowerOf2(uint x) { return (x & -x) > (x - 1); }
Very nice