On 5/21/15 4:46 PM, deadalnix wrote:
Alternatively, with bsf on could do:x << bsf(x) == 1 << [32|64]
Hm... bsf does work in your original code, I'm thinking you may have messed up bsf and bsr :)
x >> bsf(x) == 1 Which makes a LOT more sense (I tested and it works). Don't ask me why I knew bsr vs. bsf... -Steve
