On 8/11/2016 1:53 AM, John Colvin wrote:
On Thursday, 11 August 2016 at 08:45:38 UTC, Walter Bright wrote:
On 8/11/2016 1:29 AM, John Colvin wrote:
Can someone talk me through the lifetime algebra for the following?
void foo()
{
int a;
int** c;
void bar()
{
int* b = &a; <= ok, b has a smaller lifetime than a
c = &b; <= error, c has a larger lifetime than b
}
bar();
*c; //undefined behaviour
}
but according to this rule:
"For an unrestricted pointer, visibility is dictated by the usual lexical scope
rules. Lifetime, however is dictated by the lifetime of the data to which the
pointer points to."
b should have the same lifetime as a, no?
When b is assigned the address of a, then the contents of b, as accessible
through b, have the lifetime of b.
