hacky way to get explicit default constructor on struct :P

[LunaticWare via Digitalmars-d]

Event if there is no default constructor on struct we can still 
make one that work as well as if it were implemented, here is my 
example n__n

------
import std.format;
import std.stdio;

struct Player
{
    string name = "Baz";
    float[2] position = [0, 0];

    // Adding an explicit constructor to struct =)
    // But we can't enforce it since this relies on it =(
    static ref auto opCall(string name = "Bar", float x = 1, 
float y = 1)
    {
        // Even if we give no argument opCall will still be 
called ;)
        writefln("Entering the explicit constructor as '%s'", 
name);

        // Taking advantage of the implicit constructor
        Player self;

        // Initializing all the members
        self.name = name;
        self.position[0] = x;
        self.position[1] = y;

        // Returning the reference of the object
        return self;
    }

    string toString()
    {
        return format("Hello i am '%s' and at the coordinate x%s 
/ y%s",
            this.name, this.position[0], this.position[1]);
    }
}

void main()
{
    auto foo = Player("Foo", 2.7, 10.6);
    auto bar = Player();
    Player baz;

    writefln("%s\n%s\n%s", foo, bar, baz);
}

// == RDMD OUTPUT ==
// Entering the explicit constructor as 'Foo'
// Entering the explicit constructor as 'Bar'
// Hello i am 'Foo' and at the coordinate x2.7 / y10.6
// Hello i am 'Bar' and at the coordinate x1 / y1
// Hello i am 'Baz' and at the coordinate x0 / y0