On Saturday, 26 May 2018 at 12:37:15 UTC, rumbu wrote:
Therefore your first example will work correctly if you convert
the int result back to char: (char)('a' + 'b') + "sssss" will
render the correct result.
Even if C# would use '~' instead of '+', you had a type
conversion problem, not an operator problem, you wrongly
assumed that adding two chars will result in a char, not an
int. In the hypothetically code 'a' + 'b' ~ "sssss" is also
"195sssss".
I had to go back and check. Yes, it appears I screw up here.
Sorry.
Sigh, this is one of the cases whereI wish I could edit my posts.
