On Mon, 07 Nov 2011 11:51:36 -0500, Steve Teale
<steve.te...@britseyeview.com> wrote:
On Mon, 07 Nov 2011 07:17:59 -0500, Steven Schveighoffer wrote:
uint i = 5;
uint j = i;
uint k = j;
uint l = k;
If I want to make this code 64-bit aware, I need to change all 4 lines.
If these lines are scattered throughout the code, I have to play the
cyclical compiler game, where I change the first one, then compile,
change the second one, compile, etc.
Steve,
OK, you've uncovered a stark example of my ignorance there. The Types
documentation does not as far as I can see mention any differences
between a 32 bit and a 64 bit environment. It says simply that a uint is
32 bits unsigned.
What is the change that has to be made in your example?
Sorry, that is my fault. My example was too devoid of context :)
Try this instead:
int[] arr;
uint i = arr.length;
...
i.e. the change that should be made is uint => size_t.
-Steve
