On 2012-05-04 16:19, H. S. Teoh wrote:
typeof(&func) fp =&func;
And lo and behold, it works!! So it's very stupid, but if you at least
have an exemplary function that you'd like to make a function pointer
out of, you can use this workaround to name its type.
Yeah, I recommend filing a bug for this. The type of&func needs to be
nameable without resorting to using typeof(&func), but at least you can
use the latter as a temporary workaround until dmd is fixed. :-)
Just use "auto" instead of "typeof".
--
/Jacob Carlborg