On 2012-05-04 10:38, Manu wrote:
So here's some problems.
I use 'const ref' to pass structs to functions (note: because 'in ref'
doesn't seem to work)
And I often need to return structs by ref too, but I'm having problems:
void test( const ref Thing x ) {} // this works fine. note, 'const ref'
works fine here (in lieu of 'in ref')
struct Thing { }
Thing thing;
const ref Thing func() { return gThing; }
In this case the function "func" is declared const and not the return
type. The reason for this is to allow this:
class Foo
{
const:
// All methods will be const
}
It's possible to do this with all attributes.
This syntax complains, but it's precisely the same expression I use to
pass an argument in to a function, and it's fine there:
remedy\modules\hud.d(35):Error: function remedy.hud.func without
'this' cannot be const/immutable
const ref Thing function() blah = &func;
Again this declares the variable const and not the return type. I'm not
sure about the "ref" thing. I don't know if function pointers can return
by reference, at least not the syntax.
I need to take a pointer to this function, but It complains when I
declare a 'function' of this type:
remedy\modules\hud.d(36):Error: variable remedy.hud.blah only
parameters or foreach declarations can be ref (... what? it works for
parameters?)
I try rearranging the syntax to make the first issue stop complaining:
ref const(Thing) func2() { return gThing; } // this seems to work now,
but i don't like the inconsistency...
ref const(Thing) function() blah2 = &func;
This is the correct syntax to declare that it returns a const object.
Error: variable remedy.hud.blah2 only parameters or foreach declarations
can be ref
Don't know about the reference.
--
/Jacob Carlborg