On Friday, 7 September 2012 at 00:51:42 UTC, Era Scarecrow wrote:
So it seems. The way I read it says it dereferences it first. Regardless that you are forcibly referencing a pointer which is low-level trickery; which I'm sure is undefined behavior.
*Technically*, I think it is only undefined behavior once you *read* the dereferenced value... and passing by reference doesn't do that.
