On Mon, Sep 10, 2012 at 1:36 PM, Timon Gehr <timon.g...@gmx.ch> wrote:
>
> Yes, Go uses explicit pointer types.
> Regarding Rust, you are wrong.
> I have built the latest Rust compiler.
>
> import io;
>
> fn modify(&a:int){
> a = 2;
> }
> fn swap<T>(&a:T,&b:T){
> let tmp<-a;
> a<-b;
> b<-tmp;
> }
>
>
The `fn foo(&a: T)` syntax is being deprecated in favor of `fn foo(a: &mut
T)`.
So your modify function becomes: `fn modify(a: &mut int)`, and gets called
as `modify(&mut a)`.
Your swap function becomes `fn swap<T>(a: &mut T, b: &mut T)` and gets
called as `swap(&mut a, &mut b)`.
So effectively, Rust also opted for explicit ref at the call site.
--
Ziad
