Martin Braun (CEL) wrote > Given an E_b of 1, what is the noise *voltage* (i.e. the expected > amplitude of the AWGN process) that will cause an E_b / N_0 of x, if E_b > / N_0 is given in dB? > If you take pencil and paper, and solve for the noise voltage, you'll > get this equation.
Thank you very much for your reply. I am capable of simple converting value in [dB] to the one in [W/W] but I don't know why there are the number_of_bits_per_symbol parameter and the '2' constant in the equation. It's probably trivial but I would really appreciate your help on this. Best Regards, Piotr Bieńkowski -- View this message in context: http://gnuradio.4.n7.nabble.com/BER-AWGN-example-question-tp45261p45279.html Sent from the GnuRadio mailing list archive at Nabble.com. _______________________________________________ Discuss-gnuradio mailing list Discuss-gnuradio@gnu.org https://lists.gnu.org/mailman/listinfo/discuss-gnuradio
