On Mon, Dec 09, 2013 at 03:10:49AM -0800, bieniu wrote: > Martin Braun (CEL) wrote > > Given an E_b of 1, what is the noise *voltage* (i.e. the expected > > amplitude of the AWGN process) that will cause an E_b / N_0 of x, if E_b > > / N_0 is given in dB? > > If you take pencil and paper, and solve for the noise voltage, you'll > > get this equation. > > Thank you very much for your reply. I am capable of simple converting value > in [dB] to the one in [W/W] but I don't know why there are the > number_of_bits_per_symbol parameter and the '2' constant in the equation. > It's probably trivial but I would really appreciate your help on this.
The number_of_bits_per_symbol is for E_s -> E_b conversion and the 2 is for two-sided noise power to one-sided conversion (or was is the other way 'round? I always mix those up :). MB -- Karlsruhe Institute of Technology (KIT) Communications Engineering Lab (CEL) Dipl.-Ing. Martin Braun Research Associate Kaiserstraße 12 Building 05.01 76131 Karlsruhe Phone: +49 721 608-43790 Fax: +49 721 608-46071 www.cel.kit.edu KIT -- University of the State of Baden-Württemberg and National Laboratory of the Helmholtz Association
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